Heat Capacity?
A house is designed to have passive solar energy features. Brickwork is to be incorporated into the interior of the house to act as a heat absorber. Each brick weighs 2.33 kg, and the specific heat of each brick is 0.85 J/g-K. How many bricks must be incorporated into the interior of the house to provide the same total heat capacity as 2.52E3 gallons of water? {the density of water is 1.00 g/cc}
Water (liquid): cp = 4.1855 J g–1 K–1 (15 °C)
1 US gallon = 3.785 liters
1 liter masses 1 kilogram
(2.52×10^3gals)(3.785 L/gal)(1000 cc/L)(1g/cc)(4.1855J/g) = 39.9E6 J
(2.33kg)(1000g/kg)(.85J/g) = 1980.5 J/brick
(39.9E6 J)/(1980.5J/brick) = 20,157.6 bricks